(PHP 5, PHP 7, PHP 8)
stripos — Find the position of the first occurrence of a case-insensitive substring in a string
Find the numeric position of the first occurrence of
needle in the haystack string.
Unlike the strpos(), stripos() is case-insensitive.
haystackThe string to search in.
needleThe string to search for.
Prior to PHP 8.0.0, if needle is not a string, it is converted
to an integer and applied as the ordinal value of a character.
This behavior is deprecated as of PHP 7.3.0, and relying on it is highly
discouraged. Depending on the intended behavior, the
needle should either be explicitly cast to string,
or an explicit call to chr() should be performed.
offsetIf specified, search will start this number of characters counted from the beginning of the string. If the offset is negative, the search will start this number of characters counted from the end of the string.
Returns the position of where the needle exists relative to the beginning of
the haystack string (independent of offset).
Also note that string positions start at 0, and not 1.
Returns false if the needle was not found.
This function may
return Boolean false, but may also return a non-Boolean value which
evaluates to false. Please read the section on Booleans for more
information. Use the ===
operator for testing the return value of this
function.
| Version | Description |
|---|---|
| 8.2.0 | Case folding no longer depends on the locale set with setlocale(). Only ASCII case folding will be done. Non-ASCII bytes will be compared by their byte value. |
| 8.0.0 |
needle now accepts an empty string.
|
| 8.0.0 |
Passing an int as needle is no longer supported.
|
| 7.3.0 |
Passing an int as needle has been deprecated.
|
| 7.1.0 |
Support for negative offsets has been added.
|
Example #1 stripos() examples
<?php
$findme = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';
$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);
// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
echo "The string '$findme' was not found in the string '$mystring1'";
}
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>Note: This function is binary-safe.